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ANEW — Math for the Building Trades

Pre-Apprenticeship Program
Unit 4
Area & Perimeter
Math for the Building Trades — ANEW Pre-Apprenticeship Program

Vocab Key Terms

Before working through the formulas, know these terms. Tap any card to see the example.

Tap a card to expand the example.

1 Common Units & the Tape Measure

In the building trades, most measurements come from a tape measure. The tape is divided into feet, inches, and fractions of inches. Every 12 inches the tape marks a new foot.

On the job: Tape measures in the US read feet and inches. The smallest marks are 1/16 inch. The red diamonds every 19.2 inches are for truss layout. Always measure twice, cut once.
Interactive Tape Measure

Adding and Subtracting Measurements

Handle feet and inches in separate columns — just like adding two-column numbers. If inches total 12 or more, carry one foot. If subtracting more inches than you have, borrow one foot (= 12 inches) from the feet column.

Add and Subtract Feet and Inches
First
ft in
Second
ft in
Rule: Feet stay with feet, inches stay with inches. Never mix units in the same column.

2 Perimeter

A shape's perimeter is the total distance around all of its edges. On a job site, perimeter tells you how much fencing, baseboard, trim, or framing material to order. It is always measured in linear units (ft, in, m).

On the job: Ordering baseboard for a room means measuring the perimeter. Fencing a yard, running conduit around a wall, strapping a load — all perimeter problems.
Worked Example — Rectangle
A room is 14 ft long and 10 ft wide. What is the perimeter?
Step 1: Write the formula: P = 2(L + W)
Step 2: Substitute values: P = 2(14 + 10)
Step 3: Add inside the parentheses: P = 2(24)
Step 4: Multiply: P = 48 ft
P = 48 ft
Worked Example — Triangle
A triangular brace has sides 3 ft, 4 ft, and 5 ft. What is the perimeter?
Step 1: Write the formula: P = a + b + c
Step 2: Substitute: P = 3 + 4 + 5
Step 3: Add: P = 12 ft
P = 12 ft

Try It

Square — P = 4s

How to solve

Rectangle — P = 2(l+w)

How to solve

Triangle — P = a+b+c

How to solve
Square
P = 4s
Rectangle
P = 2(l+w)
Triangle
P = a+b+c
Any polygon
P = all sides

3 The Pythagorean Theorem

A right triangle has exactly one 90° angle. The side opposite that angle is the hypotenuse (c) — always the longest side. The other two sides are the legs (a and b). The Pythagorean Theorem states: a² + b² = c².

Common mistake: √(a² + b²) does NOT equal a + b. Square each leg first, then add, then take the square root. Never skip the order of operations.
Worked Example 1 — Find the Hypotenuse (3-4-5)
A right triangle has legs a = 3 ft and b = 4 ft. Find hypotenuse c.
Step 1: Write the formula: c = √(a² + b²)
Step 2: Square each leg: 3² = 9,   4² = 16
Step 3: Add: 9 + 16 = 25
Step 4: Square root: √25 = 5
c = 5 ft
Worked Example 2 — Find a Leg (10-8-6)
A right triangle has hypotenuse c = 10 ft and leg b = 8 ft. Find leg a.
Step 1: Rearrange the formula: a = √(c² − b²)
Step 2: Square the known sides: 10² = 100,   8² = 64
Step 3: Subtract: 100 − 64 = 36
Step 4: Square root: √36 = 6
a = 6 ft

Try It

Pythagorean Theorem — Solve for Any Side
On the job: The 3-4-5 rule (and multiples: 6-8-10, 9-12-15) checks square corners on slabs, walls, and decks. If the diagonal does not match c, the corner is not square.

4 Converting Between Units

The conversion factor must be applied once for every dimension. Length is 1D — multiply or divide by the factor once. Area is 2D — apply it twice (which is squaring it). Volume is 3D — apply it three times (cubing it).

FromToOperationFactorWhy
inft÷ 12121D — 12¹
ftin× 12121D — 12¹
in²ft²÷ 1441442D — 12²
ft²in²× 1441442D — 12²
in³ft³÷ 1,7281,7283D — 12³
ft³in³× 1,7281,7283D — 12³

The interactive below proves why. Step through the Area tab to see why in² needs ÷144. Then the Volume tab for ÷1,728. Use the Calculator tab to convert any value with the math shown step by step.

Square inches to square feet

1 ft = 12 in. So why divide by 144 — not 12 — to convert in² to ft²? Step through to see inside the grid.

1 / 7
The ruleRaise the conversion factor to the power of the dimension. Length: 12¹. Area: 12²=144. Volume: 12³=1,728.
Wrong144 in² ÷ 12 = 12Mixed units: 1 ft × 12 in ≠ 1 ft²
Correct144 in² ÷ 144 = 1 ft²÷12(x) × ÷12(y) = ÷12² = ÷144

Cubic inches to cubic feet

Now we add the z-axis. Each direction needs its own ÷12. Watch the cube fill in layer by layer.

1 / 7
The takeawayx, y, z — each direction needs its own conversion. 12×12×12=1,728.
Wrong1,728 in³ ÷ 12 = 144 (only x converted)
Correct1,728 in³ ÷ 1,728 = 1 ft³

Convert any measurement

Enter a value, pick a conversion, see the step-by-step math.

1D
÷ 12
in → ft
2D
÷ 144
in² → ft²
3D
÷ 1,728
in³ → ft³
Unit Conversion — Step by Step
Coming next — Unit 5: Volume. Add a third direction (the z-axis) and area becomes volume. It is the same pattern, just one more power: length = 12, area = 12² = 144, volume = 12³ = 1,728. You will build it out in Unit 5.

5 Area

A shape's area is the two-dimensional space it occupies, measured in square units (ft², in², m²). On a job site, area tells you how much flooring, roofing, concrete, paint, or siding to order.

On the job: Flooring is sold by the square foot. Roofing by the square (100 ft²). Concrete is ordered by the cubic yard — but you calculate the slab area first to get the volume. Always add 10% for waste.
Worked Example — Rectangle (from the notes)
A rectangle is 7 units wide and 4 units tall. What is the area?
Step 1: Write the formula: A = L × W
Step 2: Substitute: A = 7 × 4
Step 3: Multiply: A = 28 units²
Think about it: 7 columns of 4 unit squares each = 28 squares total.
A = 28 units²

Try It — All Shapes

Square — A = s²

How to solve

Rectangle — A = l×w

How to solve

Triangle — A = ½bh

How to solve

Parallelogram — A = bh

How to solve

Trapezoid — A = ½(b₁+b₂)h

How to solve

Circle — A = πr²

How to solve
Rectangle
A = l × w
Triangle
A = ½bh
Parallelogram
A = bh
Trapezoid
A = ½(b₁+b₂)h
Circle Area
A = πr²
Circumference
C = 2πr
Always use perpendicular height — the straight vertical distance, not the slanted side. If you are given the diameter of a circle, divide by 2 to get the radius first.

6 Composite Figures

A composite figure is a shape made from two or more simple shapes joined together. To find the area, you decompose it — break it apart into rectangles, triangles, or other shapes you already know — find each area, then add or subtract them.

On the job: Room layouts are almost never pure rectangles. An L-shaped room, a floor with a closet cut out, a deck with a notch — all composite figures. Same method every time: break it into pieces, find each piece, add them up.
Worked Example — L-Shape
An L-shaped room: total width 10 ft, total height 8 ft, with a 4 ft × 3 ft rectangle cut from the top-right corner.
Step 1: Break it into two rectangles. Rectangle A is 10 ft × 5 ft (the bottom). Rectangle B is 6 ft × 3 ft (the top-left).
Step 2: Find area of A: 10 × 5 = 50 ft²
Step 3: Find area of B: 6 × 3 = 18 ft²
Step 4: Add: 50 + 18 = 68 ft²
Total area = 68 ft²

Try It — L-Shape

Enter the outer dimensions and cutout size. The diagram updates to show how it breaks into two rectangles.

Outer Box

Cutout (top-right)

How to solve
Two strategies: (1) Add — split the shape into parts and add their areas. (2) Subtract — start with the big outer rectangle, subtract the cutout. Both give the same answer.

Ready to Practice?

The Worksheet has 136 problems covering every shape. Each problem has a labeled drawing, step-by-step how-to, and a graph view.

Unit 4 & 5 — Visual Interactive Answer Sheet

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